In a bag, there are 5 red balls, 3 blue balls, and 2 green balls. If one ball is drawn randomly and not replaced, and then a second ball is drawn randomly, what is the probability of drawing a red ball first and a blue ball second?

Question

*
2/25
15/25
5/30
15/30

Answer 1

To calculate the probability of drawing a red ball first and a blue ball second, we need to first calculate the probability of each individual event.

P(drawing a red ball first) = 5/10 (total balls in the bag)
P(drawing a blue ball second) = 3/9 (since one ball has already been drawn and not replaced)

Now, we need to calculate the probability of both events happening in sequence:
P(drawing a red ball first and a blue ball second) = P(drawing a red ball first) * P(drawing a blue ball second)
= (5/10) * (3/9)
= 15/90
= 1/6
= 5/30

Therefore, the answer is 5/30.