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in a adjoining figure,CAB is right angled triangle where AC=4cm(height),AB =3cm(base),and BC=5cm (hypotenuse),and AD is a altitude from BC .then find the length of altitude from A toBC,if its area is 6cm square.

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of course the area of ABC = (1/2)(3*4) = 6 :)

also
(1/2)(AD)(5) = 6
AD = 12/5 = 2.4 cm

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