To analyze the fertilizer composition, we need to determine the amount of each nutrient (N, P, K) based on the given ratio of 3:2:1.
In a 10 kg bag of fertilizer, the total parts of the ratio is:
\[ 3 + 2 + 1 = 6 \text{ parts} \]
Now, we can calculate the amount of each nutrient in grams:
-
Nitrogen (N): \[ \text{N} = \left(\frac{3}{6}\right) \times 10,000 \text{ g} = 5,000 \text{ g} \]
-
Phosphorus (P): \[ \text{P} = \left(\frac{2}{6}\right) \times 10,000 \text{ g} = 3,333.33 \text{ g} \]
-
Potassium (K): \[ \text{K} = \left(\frac{1}{6}\right) \times 10,000 \text{ g} = 1,666.67 \text{ g} \]
Now, let’s convert the values to grams of the actual nutrient:
- The total weight of the bag is 10,000 g.
- The amounts of N, P, and K in grams based on the ratio calculated previously seem significantly off from the choices provided, which suggests that either misunderstanding of ratios or incorrect interpretation.
Let’s consider the options given and calculate the total percentage of each option to validate if any of them maintains a ratio 3:2:1.
Starting with the provided ratios:
Option a) \(400g N, 800g P, 1200g K\)
- Sum: \(400 + 800 + 1200 = 2400g\)
- Ratio check: \(3:2:1 \neq 400:800:1200\) (fails)
Option b) \(40g N, 80g P, 120g K\)
- Sum: \(40 + 80 + 120 = 240g\)
- Ratio Check: \(3:2:1 \neq 40:80:120\) (fails)
Option c) \(1200g N, 800g P, 400g K\)
- Sum: \(1200 + 800 + 400 = 2400g\)
- Ratio Check: \(3:2:1 \neq 1200:800:400\) (fails)
Option d) \(120g N, 80g P, 40g K\)
- Sum: \(120 + 80 + 40 = 240g\)
- Ratio Check: \(3:2:1 \neq 120:80:40\) (fails)
None of the options are consistent with the 3:2:1 ratio expected in a 10 kg fertilizer bag. Therefore, the correct answer is f) None of the above.