In a 1-dimensional problem, a single force acts on a 10 kg object and is given the equation F=ax+b where a=250 N/m, b=25 N, x is position of object. There is a force acting on the object while that object moves from x=0 to x=2 lasting 3 sec.

Question

1) What is the work done by this force during the time interval?
What is the average power developed by this force during the time interval.
If the object was at rest when x=0, what is the kinetic energy of the object at x=2m


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Answer 1

1. F = 250*2 + 25 = 525 N.
Work = F*d = 525 * 2 = 1050 Joules.

2. P = F*d/t = 525 * 2/3 = 350 J/s. =
350 Watts.