........HClO ==> H^+ + OCl^-
I.....1.0E-4.....0........0
C........-x.......x.......x.
E......1E-4-x.....x.......x
Ka = (H^+)(OCl^-)/(HClO)
Substitute and solve for x = (H^+) = (OCl^-). (HClO) = 1.00E-4-x
You can get OH from
(H^+)(OH^-) = Kw
In a 1.0x10^-4 M solution of HClO(aq), identify the relative molar amounts of these species:HClO, OH-, H3O+, OCl-, H2O
4 answers
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H2O, HClO, H3O+, OH-, OCl-
most -> least: H20, HClO, H3O+, OCl-, OH-