Have you tried to read what you post with no periods? Where the hell does the sentence end and the next one start. Fortunately I know enough chemistry that I may be able to guess. You can hope that I guess right.
........2NH3 ==> N2 + 3H2
I........0......1.3....1.65
C.......+2x......-x....-3x
E....... 2x....1.3-x...1.65-3x
The problem tells you that 2x = 0.100.
Solve for x and evaluate 1.3-x and 1.65-3x
In a 1.00 L container at 272 degrees C 1.3 mol of N2 and 1.65 mol of H2 are added at equilibrium 0.100 mol NH3 is present calculate the equilibrium concentrations of N2 and H2
2NH3(g)<-->N2(g)+3H2(g)
1 answer