Asked by Manal
In 400min,2.4grams of copper is obtained by Cu2+ solution,find how many Amphere is required for this experiment. Using the same current and time what mass of Cu2+ will be obtained from a Cu(NO3)2.
Answers
Answered by
bobpursley
you need 2 electrons per ion to flow.
current= charge/timeinSeconds
= 2elec/atom*charge/electron* (atoms/gram)*grams/time checking units...
= 2(elec/atom)1.6e-19Coul/elec*(6.02e23 atoms/63.5g)*(2.4grams)/time
= 2*1.6e-19*6.02e23*2.4/63.5 /(time) coulombs
7.28e3 C /timeinseconds
or current=7.28e3 /400*60 sec= .30amps
check that, it is easy to err when typing.
current= charge/timeinSeconds
= 2elec/atom*charge/electron* (atoms/gram)*grams/time checking units...
= 2(elec/atom)1.6e-19Coul/elec*(6.02e23 atoms/63.5g)*(2.4grams)/time
= 2*1.6e-19*6.02e23*2.4/63.5 /(time) coulombs
7.28e3 C /timeinseconds
or current=7.28e3 /400*60 sec= .30amps
check that, it is easy to err when typing.
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