In 2010 a city raised $5,999,400 in tax revenue by charging each taxpayer the same amount. For 2011 there has been a net loss of 12 taxpayers, necessitating an increase fo $200 per taxpayer in order to maintain the tax revenue of $5,999,400. How many taxpayers were there in 2010?

Answer 1

X-Taxpayers in 2010.

(X - 12)Taxpayers in 2011.

$200(X - 12) = $5,999,400.
X - 12 = 29997 Taxpayers in 2011.

Answer 2

X - 12 = 29997,
X = 30009 Taxpayers in 2010.