You would do well to keep the same screen name. We can help better if you do that.
rate = 1/2*d(NO2)/dT
d(NO2) = 450-320 = 130
dT = 20
rate formation O2 is 2x rate NO2 decomposition
In 20 s, the concentration of NO2 decreases from 450 mM to 320 mM in the reaction
2 NO2 --> 2 NO + O2
(a) Determine the rate of reaction of NO2
(b) Determine the rate of formation of O2
(c) What is the unique rate of the reaction?
1 answer
1 answer