implicit differentation

1.y^3=4(x^2+y^2)
2.y^2-3x+2y=0

help please

You consider y to be a function of x, but you don't explicitely solve for it. Then you formally differentiate w.r.t. x using the chain rule:

y^3(x) = 4(x^2+y^2(x)) --->

3y^2dy/dx = 8x + 8y dy/dx

y^2-3x+2y=0 --->

2ydy/dx - 3+2dy/dx = 0

Ask a New Question or answer this question.

Similar Questions

(cos πx + sin πy)4 = 54; Implicit Differentation
1. 3 answers
Find dy/dx by implicit differentation.ysin(x^2)=-xsin(y^2)
1. 2 answers
If ln(x^2-15y)=x-y+5 and y(-4) by implicit differentation =Thus the equation of the tangent line to the graph at point (-4,1) is
1. 1 answer
7y^4+x^3y+x=4using implicit differentation, how do i solve this problem. it is a textbook example but the partwhere i "use the
1. 6 answers