Imagine we have two identical batteries with emf = 1.8V and an internal resistance of 0.6 ohms. Now we connect the batteries to a circuit with total resistance of 50 ohms. What is the maximum amount of power we can dissipate in the 50 ohm load? what is the minimum?

Answer 1

depends on how the batteries are connected, series or parallel.

Assuming series:
power=I^2(50)
where I= (2*1.8 )/51.2