Asked by Suzy
Imagine we have two identical batteries with emf = 1.8V and an internal resistance of 0.6 ohms. Now we connect the batteries to a circuit with total resistance of 50 ohms. What is the maximum amount of power we can dissipate in the 50 ohm load? what is the minimum?
Answers
Answered by
bobpursley
depends on how the batteries are connected, series or parallel.
Assuming series:
power=I^2(50)
where I= (2*1.8 )/51.2
Assuming series:
power=I^2(50)
where I= (2*1.8 )/51.2
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