Imagine a scenario in which an animal's force is pushing itself forward 5 N, friction is pushing it 4 N backward, gravity is pushing the animal 10 N down, and the animal is pushing itself 10 N up. Describe the movement of the animal.(1 point)

Question

Responses

It only moves forward because there is a net force forward.
It only moves forward because there is a net force forward.

It moves 10 N down and 10 N up as those are the greatest forces acting on the animal.
It moves 10 N down and 10 N up as those are the greatest forces acting on the animal.

It moves forward and upward because those are the greatest net forces.
It moves forward and upward because those are the greatest net forces.

It moves 29 N forward because that's the net force.

Answer 1

To analyze the scenario, we need to look at the forces acting on the animal:

1. The force propelling the animal forward: 5 N (forward).
2. The frictional force opposing its forward motion: 4 N (backward).
3. The gravitational force acting downward: 10 N (down).
4. The force the animal exerts to push itself upward: 10 N (up).

Now, let's calculate the net forces:

• Net force forward/backward: \[ 5 , \text{N (forward)} - 4 , \text{N (backward)} = 1 , \text{N (forward)} \]

• Net force up/down: \[ 10 , \text{N (up)} - 10 , \text{N (down)} = 0 , \text{N} \]

The net force in the upward/downward direction is zero, meaning there is no vertical movement. However, there is a net force of 1 N in the forward direction.

Therefore, the correct response is:

It only moves forward because there is a net force forward.