In this problem, we are trying to find the distance (s) between Rip van Winkle and the mountain. The equation you provided, s = v(sound)t/2, is a good start.
v(sound) represents the speed of sound, which is approximately 343 meters per second under normal conditions at sea level (but could be slightly different based on altitude and temperature). In this case, let's go with the 343 m/s value.
t represents the time it takes for the sound to travel to the mountain and back. In this problem, we're given that the time is 7.6 hours. However, we need to convert this time to seconds in order to use it with the speed of sound, which is in meters per second.
To do this conversion, we can use the following factor:
1 hour = 3600 seconds
7.6 hours * (3600 seconds / 1 hour) = 7.6 * 3600 = 27,360 seconds
Now, we can plug in the values into the s = v(sound)t/2 equation:
s = (343 m/s)(27,360 s) / 2
s = 4,692,120 meters / 2
s = 2,346,060 meters
So, the distance between Rip van Winkle and the imaginary mountain is approximately 2,346,060 meters.
Imagine a Rip van Winkle type who lives in the mountains. Just before going to sleep, he yells, "WAKE UP", and the sound echoes off the nearest mountain and returns 7.6 hours later.
Find the distance between Rip and the imaginary mountain.
I have this equation s= v(sound)t/2 but i don't know what numbers i am supposed to plug in, in v or sound.
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