Bot, Please answer this question
1.Find the mean of the data
98 132 295 68 176 89 287 198 94 68 240 94 369 94 155
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1. in the figure , the areas of traingle cef, triangle abe, triangle adf are 3,4, and 5 respectively. find the area of triangle aef
2. equialateral triangle abc has an area of square root of 3 and side of length 2. point p is an arbitrary point in the interioir of the traignle. what is the sum of the distances from p to ab, ab, and bc?
3. in the accompanying firgure , abcd is a square . suppose be=3 cm, ec=1cm and p is a point on the diagonal bd. find the smallest possible value of pe + pc in cm.
4. in triangle abc, ab=7, ac=9. on ab, point d is taken so that bd = 3. de is drawn cutting ac in e so that quadrilateral bced has 5/7 the area of trangile abc. find ce.
5. find the ratio between the area of a square inscribed in a circle and an equilateral circumscribed about the same circle.
9 answers
To find the mean (average), add up all the data points and divide by the total number of data points:
98 + 132 + 295 + 68 + 176 + 89 + 287 + 198 + 94 + 68 + 240 + 94 + 369 + 94 + 155 = 2179
There are 15 data points, so:
Mean = 2179/15 = 145.27
Therefore, the mean of the data is approximately 145.27.
98 + 132 + 295 + 68 + 176 + 89 + 287 + 198 + 94 + 68 + 240 + 94 + 369 + 94 + 155 = 2179
There are 15 data points, so:
Mean = 2179/15 = 145.27
Therefore, the mean of the data is approximately 145.27.
Bot, Please answer this question
Find the median of the data
98 132 295 68 176 89 287 198 94 68 240 94 369 94 155
Find the median of the data
98 132 295 68 176 89 287 198 94 68 240 94 369 94 155
To find the median, we first need to arrange the data in order:
68, 68, 89, 94, 94, 94, 98, 132, 155, 176, 198, 240, 287, 295, 369
There are 15 data points, so the median is the middle value. In this case, since there are an odd number of data points, the middle value is the 8th value:
Median = 132
Therefore, the median of the data is 132.
68, 68, 89, 94, 94, 94, 98, 132, 155, 176, 198, 240, 287, 295, 369
There are 15 data points, so the median is the middle value. In this case, since there are an odd number of data points, the middle value is the 8th value:
Median = 132
Therefore, the median of the data is 132.
Bot, Please answer this question
Find the mode of your data
98 132 295 68 176 89 287 198 94 68 240 94 369 94 155
Find the mode of your data
98 132 295 68 176 89 287 198 94 68 240 94 369 94 155
The mode is the data point(s) that appear most frequently in the data set. In this case, the number 94 appears three times, while all other numbers appear no more than two times. Therefore, the mode of the data set is:
Mode = 94
Therefore, the mode of the given data is 94.
Mode = 94
Therefore, the mode of the given data is 94.
Bot, Please answer this question
Find the range of the data
98 132 295 68 176 89 287 198 94 68 240 94 369 94 155
Find the range of the data
98 132 295 68 176 89 287 198 94 68 240 94 369 94 155
The range of a data set is the difference between the largest and the smallest value in the data set.
In this case, the smallest value is 68 and the largest value is 369.
Range = Largest value - Smallest value
Range = 369 - 68
Range = 301
Therefore, the range of the given data is 301.
In this case, the smallest value is 68 and the largest value is 369.
Range = Largest value - Smallest value
Range = 369 - 68
Range = 301
Therefore, the range of the given data is 301.
Bot, Please answer this question
Find the interquartile range (IQR) of the data
98 132 295 68 176 89 287 198 94 68 240 94 369 94 155
Find the interquartile range (IQR) of the data
98 132 295 68 176 89 287 198 94 68 240 94 369 94 155