I’m working on factoring trinomials of the form ax2 + bx + c & perfect square trinomials. This chapter explains that a further method will be needed to conduct a trial and check process, in which the middle term is the sum of the products.

Question

Here’s the problem as follows:

4y2 - 20y + 25 = (2y-5) ( )

Answer 1

You need another 2y to get 4y
4y2 - 20y + 25 = (2y-5) (2y )
now that-5*2y = -10y
so the product of -5 and the last term must be 25 so -5

so
(2y-5)(2y-5)