Asked by Johnny
I'm trying to find why the linear function f(-x)=x√x^2+2 is negative when it should be neither. why are √'s not negatives?!?!?! Is it because √x can't cross over the y axis because √x can't be negative? Then why is it that the x on the outside of the function is negative and the whole thing is counted as a neither?!
Answers
Answered by
Reiny
First of all your function is not a linear function, (it is not a straight line)
Secondly, is it the way you typed it or is it
f(-x) = x√(x^2 + 2)
by the way,
f(x) = -x√(x^2+2)
for negative x's the graph rises in quadrant II
for positive x's the graph drops in quadrant IV
it crosses the x-axis at (0,0)
Wolfram shows this:
http://www.wolframalpha.com/input/?i=-x√%28x%5E2%2B2%29
Secondly, is it the way you typed it or is it
f(-x) = x√(x^2 + 2)
by the way,
f(x) = -x√(x^2+2)
for negative x's the graph rises in quadrant II
for positive x's the graph drops in quadrant IV
it crosses the x-axis at (0,0)
Wolfram shows this:
http://www.wolframalpha.com/input/?i=-x√%28x%5E2%2B2%29
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