I'm stumped

4ko2 + 2co2 ----2k2co3 + 3o2

What mass of k02 in grams is required to react with 8.90 l at 22.0 c and 767 mm hg?

Please help thank you

1 answer

Please note that you will not get anywhere in chemistry, probably flunk out, it you don't find and use the caps key. You must know where it is for you started sentences with a capital letter and I must congratulate you on ending the sentences properly BUT lower case and upper case letters in chemistry mean different things. For example, CO vs Co vs co OR m vs M. Also note that you didn't react the KO2 with anything. I assume you meant 8.90 L CO2. If not ignore the rest of this.

Use PV = nRT and convert 8.90L CO2 to n = mols CO2.
Using the coefficients in the balanced equation, convert mols CO2 to mols KO2.
Then convert mols KO2 to grams. g KO2 = mols KO2 x molar mass KO2.
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