a-b(x+c)=d
just follow the order of operations
a - bx - bc = d
keep the term containing x, move everybody else to the other side
- bx = d - a + bc
divide each term by -b
x = -d/b + a/b - c
or
x = (d-a+bc)/-b
or
x = (a - d - bc)/b
the fact that all variables are positive is of no concern, other than b cannot be zero
I'm so confused on how to solve this problem~
a-b(x+c)=d
I'm supposed to solve for x and all of the variables are positive -_-
I'm lost
5 answers
I'm still confused though~
so x= (d-a+bc)/-b?
and those 3 answers given are the final things you can do?
so x= (d-a+bc)/-b?
and those 3 answers given are the final things you can do?
I also have to solve for x~
a(bx-c)=d-(x+e)
again, all variables represent positive #s
a(bx-c)=d-(x+e)
again, all variables represent positive #s
follow the same steps as before
first expand
a(bx-c)=d-(x+e)
abx - ac = d - x - e
get all the x terms to one side, everybody else to the other side
abx + x = d + ac - e
divide everybody by ab, that would leave the x all alone
x = (d+ac-e)/(ab)
all done
first expand
a(bx-c)=d-(x+e)
abx - ac = d - x - e
get all the x terms to one side, everybody else to the other side
abx + x = d + ac - e
divide everybody by ab, that would leave the x all alone
x = (d+ac-e)/(ab)
all done
ok thank you I think I understand now