Note the correct spelling of celsius.
mols C10H8 = grams/molar mass = 7.58/molar mass C10H8 = ?
Then molality = m = mols/kg solvent
m = mols from above/0.120 = ?
Then delta T = Kb*m. You know Kb and m, solve for delta T, then add that to the normal boiling point of benzene in the problem to find the new boiling point.
I'm really confused on this question so if someone could show the steps and how to get the answer, that would be great. I understand that you would use delta T=Kbm, but don't know how to use the equation to find the answer. Thanks!!
Calculate the boiling point of a solution containing 7.58 grams of C10H8 in 120.0 grams of benzene. The boiling point of benzene is 80.1 degrees Celcius and the Kb = 2.52 degrees celcius/molal.
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I know what I did wrong. Some reason I divided the moles of C10H8 by .0120 instead of .120, so my answer was 11 times the answer it should have been. Thank you very much!
1 answer