Asked by Alycia
I'm only aloud to manipulate one side of the problem and the end result has to match the other side of the equation
Problem 1. sinx + cosx + sinx + tanx + cosxcotx = secx + cscx
Problem 2. ((sinx + cosx)/(1 + tanx))^2 + ((sinx - cos^2x)/(1 - cotx))^2 = 1
Problem 3. ((1 + sinx)/cosx) + (cosx/(1 + sinx)) = 2secx
Problem 1. sinx + cosx + sinx + tanx + cosxcotx = secx + cscx
Problem 2. ((sinx + cosx)/(1 + tanx))^2 + ((sinx - cos^2x)/(1 - cotx))^2 = 1
Problem 3. ((1 + sinx)/cosx) + (cosx/(1 + sinx)) = 2secx
Answers
Answered by
Reiny
I did the first one, after fixing your typo
http://www.jiskha.com/display.cgi?id=1351823844
http://www.jiskha.com/display.cgi?id=1351823844
Answered by
Reiny
#2 does not work for x=30° so there is a typo, or it is not and identity.
#3
LS = (1+sinx)/cosx + cosx/(1+sinx)
using LCD of cosx(1+sinx)
= ( (1+sinx)(1+sinx) + cos^2 x)/(cosx(1+sinx) )
= 1 + 2sinx + sin^2 x + cos^2 x)/(cosx(1+sinx) )
= (2 + 2sinx)/(cosx(1+sinx))
= 2(1+sinx)/(cosx(1+sinx))
= 2/cosx
= 2secx
= RS
#3
LS = (1+sinx)/cosx + cosx/(1+sinx)
using LCD of cosx(1+sinx)
= ( (1+sinx)(1+sinx) + cos^2 x)/(cosx(1+sinx) )
= 1 + 2sinx + sin^2 x + cos^2 x)/(cosx(1+sinx) )
= (2 + 2sinx)/(cosx(1+sinx))
= 2(1+sinx)/(cosx(1+sinx))
= 2/cosx
= 2secx
= RS
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.