unlessss....
I just solve for mass and the 20 kiloton is just extra useless information meant to throw people off and do this:
e=mc^2 m = E/c^2
m = 8*10^13 J / (3.0*10^8 m/s)^2
m= 8.89 * 10 ^-4 kg hmm
I'm not too good with these special relativity problems :/
The question is: A 20 kiloton bomb releases 8 x 10^13 joules. How much mass must be converted into other forms of energy?
You are already given Energy, would I still use the E=mc^2 formula??
E=(2.0*10^7 kg)(3*10^8 m/s)^2 ?
3 answers
I agree with this:
e=mc^2 m = E/c^2
m = 8*10^13 J / (3.0*10^8 m/s)^2
m= 8.89 * 10 ^-4 kg hmm
A gram of mass is a lot of energy.
e=mc^2 m = E/c^2
m = 8*10^13 J / (3.0*10^8 m/s)^2
m= 8.89 * 10 ^-4 kg hmm
A gram of mass is a lot of energy.
thank you! How would I know not to use the mass of 20 kilotons though? I wish they didn't put that in the question it really throws you off haha
2 answers