f(x) = ∫[0,x] 2πu du
df/dx = 2πx
you are correct. I suspect that those choices belong to a different problem, or that there is a misprint in this one.
I'm not sure how to solve this and help would be great!
d/dx [definite integral from 0 to x of (2pi*u) du] is:
a. 0
b. 1/2pi sin x
c. sin(2pi x)
d. cos (2pi x)
e. 2pi cos (2pi x)
This is the fundamental theorem, right? What's confusing me is the u and du and the end. At first I thought it was 2pi but that isn't an option. Then I thought that maybe it's zero because u would be =2pi and du would be 0, so 0 times the integral would be 0. Can someone help me?
1 answer
1 answer