x³-4x
=x(x²-4)
=x(x+2)(x-2)
A few identities that may help you while you're on the subject:
A²-B²=(A+B)(A-B)
A³-B³=(A-B)(A²+AB+B²)
A³+B³=(A+B)(A²-AB+B²)
A⁴-B⁴
=(A²+B²)(A²-B²)
=(A²+B²)(A+B)(A-B)
I'm not sure how to factor x^3-4x is greater than/equal to 0 so that I can find the zeroes. Can you demonstrate, please?
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