a. At its highest point, the vertical component of velocity is zero. The horizontal component is as in the beginning (10cos(30°)).
b. calculate using the kinematics formulas as if it is thrown upwards with an initial velocity of 10sin(30°).
Using conservation of energy,
At the beginning, the potential energy is mg*0. The kinetic energy is (1/2)m(10)².
At the top: the potential energy is mgh, the kinetic energy is (1/2)mv² (v=10cos(30°)).
Equate and solve for h.
I'm not sure how to do this problem
A .40 kg ball is thrown with a speed of 10 s^-1 m at an angle of 30 degrees. (a) What is its speed at its highest point, and (b) how high doe it go? (Use conservation of energy.)
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