I'm here at a study group with Aaron and while he's stuck on that question, I'm stuck on this one... I think we're gonna take a break but I'd love if someone could help break this down for me.
Carbon monoxide, CO, and hydrogen, H , react according to the reaction below.
2 CO(g) + 5 H (g) --> C H (g) + 2 H O(g)
What volume of the excess reactant remains if 18.6 L CO and 32.2 L H are allowed to react. Assume that the volumes of both gases
are measured at 735 C and 1.19 atm.
Give your answer in litres, accurate to two significant figures.
3 answers
first change everything to moles, and then recall that at STP, 1 mole occupies 22.4L of volume.
@Steve
Moles of CO2 and H? once I find the moles do I use PV=nRT --> V=nRT/P?
Moles of CO2 and H? once I find the moles do I use PV=nRT --> V=nRT/P?
Can you give me the answer so I can try and work backwards. I'm really lost. you don't need to show the steps now that i have the process, I'll get there i just want to know if i get the answer right
1 answer