Question

Im having trouble finding out what the graphs would look like for these kinematic equations

a.v=vox
b.dx=dox + voxt
c. vy=voy +gt

d. dy= doy +voyt +1/2gt^2

can someone explain to me what the graphs would look like and why?

Answer 1

1. Velocity in the x direction is constant and equal to the original x velocity

2. the x position is the original position + Vox T
straight line with slope Vox and x intercept of Dox

3. In the vertical direction velocity is a straight line versus time with intercept of Voy and slope of g (g is usually negative, down, gravity)

4. Dy or height is a parabola versus time = initial height Dyo + Voy t + (1/2) g t^2

Answer 2

wait so a is a line that goes upp
b. is a straight line across?
c. a straight line going down
d. a parabola?

Answer 3

a. yes, same x speed for any t

b. slopes up with slope = Vox
Dx = Vox * t + Dox looks like
x = m * t + b

c. slope g, not straight down
again of form y = m * t + b

d yes, a parabola