I'm having trouble figuring this out. An airplane has an airspeed of 160 mph. It is to make a flight in a direction of 80° while there's a 20 mph wind from 310°. What will the airplane's actual heading be?

Question

I'm having trouble figuring this out. An airplane has an airspeed of 160 mph. It is to make a flight in a direction of 80° while there's a 20 mph wind from 310°. What will the airplane's actual heading be? 
I'd appreciate any help especially on how you determined what angles to use. Thank you.

Henry · Answer

Vr = 160[80o] + 20[310o] = Resultant velocity. Vr = (160*Cos80+20*Cos310) + (160*sin80+20*sin310)i Vr = 40.64 + 142.25i = 147.7mph[74.1o] Heading = 74.1o