just convert everything to x-y values, add them up, and change back to headings. If his heading is θ, then we need
160sinθ - 20sin310° = v*sin80°
160cosθ - 20cos310° = v*cos80°
solve that and you get
θ = 74.5°
v = 172.1
makes sense, since the wind is blowing to the SE, adding to his speed.
I'm having trouble figuring this out. An airplane has an airspeed of 160 mph. It is to make a flight in a direction of 80° while there's a 20 mph wind from 310°. What will the airplane's actual heading be?
I'd appreciate any help especially on how you determined what angles to use. Thank you.
1 answer
1 answer