whenever you see brackets with no number in front as multipliers, imagine that you have a 1 in front
so the third one becomes
1(6h+1)-1(9h+4)
now expand it to get
6h + 1 - 9h - 4
= -3h - 3
now you try the others, let me know what you get.
I'm having a hard time in math, and every time I start my test my eyes glaze over. Can anyone please help me out?
(9m+6)+(-5m-6)
(3r^2+7r+1)+(4r^2-8r-2)
(6h+1)-(9h+4)
(-7w^2-2w-1)-(-5w^2 +3w-2)
1 answer