I'm getting this answer wrong, can someone please help show me what i'm missing?? thank you :)
Infinity of the summation n=0: [(-1)^n pi^(2n)] / [6^(2n) (2n)!]
this is my work:
[(-1^0) pi^(2*0)] / [6^(2*0) (2*0)!] + [(-1^1) pi^(2*1)] / [6^(2*1) (2*1)!] + [(-1^2) pi^(2*2)] / [6^(2*2) (2*2)!] + [(-1^3) pi^(2*3)] / [6^(2*3) (2*3)!]
-1 + -0.13707783 + -0.00313172 + -0.0000286 + -0.00000014
sum of the series = -1.14023829
You got the signs wrong. The answer is 1/2 sqrt[3]
thank you!!!