I might have figured it out and it was easier than I though it was if I'm correct.
Does this look right?....
Lower Limit = mean - 2SD
and
Lower Limit = 9.2 mg/dl
9.2 = ((9.2+10.2)/2) - 2SD
2SD = 0.5
SD = 0.25??
I'm confused on how to calculate the standard deviation for this...
The 95% confidence limit for calcium in control sera is reported as 9.2-10.2 mg/dl. Calculate the value for one standard deviation and the coefficient of variation for this data.
1 answer
1 answer