ifx^3+mx^2+nx+6 has x-2 as a factor and leaves remainder 3 when divided by x-3, find the values of m and n.

Answer 1

let f(x) = x^3 + mx^2 + nx + 6
given:
f(2) = 0
= 8 + 4m + 2n + 6 = 0 ---> 2m + n = -7
given: f(3) = 3
= 27 + 9m + 3n + 6 = 3 --- 3m + n = -10

subtract the two equations to get : m = -3
sub that into 2m+n=-7
-6 + n = -7
n = -1

m= -3, n = -1

Answer 2

Ajib sa answer h😂