Ifsin=12/13,find the value of sin²_cos²/2sin2cosx1/tan²

Answer 1

sin²_cos²/2sin2cosx1/tan²
re-enter in proper form

e.g. sin = 12/13 is meaningless, "sin" is an operator and needs an operand
did you mean :
sinØ = 12/13 or sinx = 12/13 ??
that is like saying √ = 3 , or log = 1.3

Answer 2

and aside from that, what does 2sin2cos mean?

Try actually writing sin^2x or cosx or sin2x or something so we can tell the angles being used.

In any case, if sinx = 12/13 then cosx = 5/13, tanx = 12/5

Now just plug in those fractions for whatever expression you want to evaluate.