If zeros of p(x)=2x2-7x+k are reciprocals of each other,then find the value of me

Answer 1

If the roots are a and 1/a, then

a*1/a = k/2

k=2

2x^2-7x+2 has roots

(7±√33)/4
and, it happens that (7-√33)/4 = 4/(7+√33)

Answer 2

If zeroes of p(x) = 2x2
– 7x + k are reciprocal of each other, then find the value of k.