To find the product of z3 and z4, we can use the distributive property of complex numbers:
z3 * z4 = (3 + 2i) * (4 + 3i)
Using FOIL (First, Outer, Inner, Last), we can multiply the terms:
= 3 * 4 + 3 * 3i + 2i * 4 + 2i * 3i
= 12 + 9i + 8i + 6i^2
= 12 + 17i + 6(-1) (since i^2 = -1)
= 12 + 17i - 6
= 6 + 17i
Therefore, the product of z3 and z4 is 6 + 17i.
If z3=3+2i and z4=4+3i. Then, z3 z4 is
Question 9 Select one:
6-17i
7+17i
5+16i
6+17i
1 answer