If z square+kz+3 of 8 equal parts is a perfect square then k is?

1 answer

Given the expression \( z^2 + kz + 3 \), we want to find the values of \( k \) for which this expression can be expressed as a perfect square.

For the quadratic \( z^2 + kz + 3 \) to be a perfect square, it must equal \( (z + a)^2 \) for some real number \( a \). Expanding the perfect square gives us:

\[ (z + a)^2 = z^2 + 2az + a^2 \]

By comparing coefficients, we can match terms from both quadratic expressions:

  1. The coefficient of \( z \): \[ k = 2a \]
  2. The constant term: \[ 3 = a^2 \]

From the equation \( 3 = a^2 \), we have:

\[ a = \sqrt{3} \quad \text{or} \quad a = -\sqrt{3} \]

Using both values of \( a \), we can find \( k \):

  1. If \( a = \sqrt{3} \): \[ k = 2\sqrt{3} \]
  2. If \( a = -\sqrt{3} \): \[ k = -2\sqrt{3} \]

Thus, the possible values for \( k \) that make \( z^2 + kz + 3 \) a perfect square are:

\[ k = 2\sqrt{3} \quad \text{or} \quad k = -2\sqrt{3} \]