0.9656
Since z is a standard normal variable, the probability that z is greater than -1.82 can be found by looking up the Z-score for -1.82 in a standard normal distribution table.
The Z-score for -1.82 is 0.0344, which means that 96.56% of the distribution is greater than -1.82. Therefore, the probability that z is greater than -1.82 is 0.9656.
If z is a standard normal variable, find the probability.
The probability that z is greater than –1.82.
(1 point)
Responses
–0.0344
0.9656
0.0344
0.4656
1 answer