If z˅1=1+2j and z˅2=1+j find

Question

(i) z˅1-3z˅2

(ii) z˅1z˅2
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(iii) z˅1z˅1

(iv) z˅1/z˅2

Answer 1

v1 - 3v2 = (1+2j)-3(1+j) = 1+2j-3-3j = -2-j

v1*v2 = (1+2j)(1+j) = 1+3j+2j^2 = -1+3j

v1*v1 = (1+2j)(1+2j) = -3+4j

v1/v2 = (1+2j)/(1+j) * (1-j)/(1-j) = (3+j)/2

you can practice you skills at wolframalpha.com, but use i instead of j.