If you write the function P=10e^−2t in the form P=P0a^t, then
P0=
a=
.
2 answers
come on now !!
Did not notice the change in the exponent.
so
P=10e^−2t
= 10(e^-2)^t
= 10(1/e^2)^t
now compare with P=P0a^t
so
P=10e^−2t
= 10(e^-2)^t
= 10(1/e^2)^t
now compare with P=P0a^t