your weight (gravitational attraction to the Earth)
... is directly proportional to the product of the masses (you and Earth)
... and is inversely proportional to the square of the distance between the centers of mass
690 N * 6 / (4^2)
If You weigh 690 N.
What would you weigh if the Earth were six
times as massive as it is and its radius were
four times its present value?
Answer in units of N.
Need help i don't know how this
2 answers
you have to figure the new radius, which is 4R.
Notice weight= constant*Mass/(R^2)
so witth the change, M is now 6M, , and R^2 becomes (4R)^2 or 16R^2
so as I see it, weight is now original weight*6/16
Notice weight= constant*Mass/(R^2)
so witth the change, M is now 6M, , and R^2 becomes (4R)^2 or 16R^2
so as I see it, weight is now original weight*6/16
1 answer