If you watch little kids try to open doors, they will often just push anywhere on the door, rather than on the edge like adults do. This is because they don't understand that it's easier to open a door if you push on the edge. But how much easier? Consider the following situation: you push on a door perpendicularly at a horizontal distance x0 from the hinge with a force F0, thereby opening the door with some angular acceleration α. Let F1 be the amount of force you'd need to exert to open the door with the same angular acceleration, but pushing perpendicularly at a horizontal distance 2x0 from the hinge. What is F1/F0?
3 answers
please answer its urgent
The second law for rotation
M=Iα => α=M/I
M₁/I₁=M₀/I₀ =>
M₁/M₀=I₁/I₀
I₁ = I₀ =>
M₁ = M₀
F₁x₁=F₀x₀
F₁/F₀=x₀/x₁=x₀/2x₀ =1/2
M=Iα => α=M/I
M₁/I₁=M₀/I₀ =>
M₁/M₀=I₁/I₀
I₁ = I₀ =>
M₁ = M₀
F₁x₁=F₀x₀
F₁/F₀=x₀/x₁=x₀/2x₀ =1/2
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