a sum of 7 has a prob of 6/36 = 1/6
to get a 7:
16, 25, 34, 43, 52, 61 ----> 6 of them
all other sums have a lesser count
e.g.
to get a 5:
14, 23, 32, 41, --- only 4 of them
if you tossed two number cubes, what sum has the greatest probability of occuring? Explain.
5 answers
well this is no help at all so take this website down now
Look at the list. 7 is in all of the lists, so 7 is the answer.
1,1=2
1,2=3
1,3=4
1,4=5
1,5=6
1,6=7
----------------------------------
2,1=3
2,2=4
2,3=5
2,4=6
2,5=7
2,6=8
----------------------------------
3,1=4
3,2=5
3,3=6
3,4=7
3,5=8
3,6=9
-----------------------------------------
4,1=5
4,2=6
4,3=7
4,4=8
4,5=9
4,6=10
-----------------------------------------
5,1=6
5,2=7
5,3=8
5,4=9
5,5=10
5,6=11
--------------------------------------------
6,1=7
6,2=8
6,3=9
6,4=10
6,5=11
6,6=12
1,1=2
1,2=3
1,3=4
1,4=5
1,5=6
1,6=7
----------------------------------
2,1=3
2,2=4
2,3=5
2,4=6
2,5=7
2,6=8
----------------------------------
3,1=4
3,2=5
3,3=6
3,4=7
3,5=8
3,6=9
-----------------------------------------
4,1=5
4,2=6
4,3=7
4,4=8
4,5=9
4,6=10
-----------------------------------------
5,1=6
5,2=7
5,3=8
5,4=9
5,5=10
5,6=11
--------------------------------------------
6,1=7
6,2=8
6,3=9
6,4=10
6,5=11
6,6=12
7 because it is the number which is the nearest number to the middle.
(0.5 meant add 1)
(0.5 meant add 1)
That's correct! Another way to explain it is that there are 6 different ways to get a sum of 7 when tossing two number cubes (1+6, 2+5, 3+4, 4+3, 5+2, 6+1), which is more than any other possible sum. Therefore, the sum of 7 has the greatest probability of occurring.