If you toss a coin and roll a number cube, what is the probability of obtaining a head and rolling a 6? Round your answer to the nearest hundredth if using a decimal.

1 answer

To find the probability of both events occurring (tossing a head on a coin and rolling a 6 on a number cube), we can use the multiplication rule for independent events.

  1. Probability of tossing a head: The probability of getting a head when tossing a fair coin is \( \frac{1}{2} \).

  2. Probability of rolling a 6: The probability of rolling a 6 on a standard number cube (which has 6 faces) is \( \frac{1}{6} \).

Now, we multiply these probabilities together:

\[ P(\text{head and 6}) = P(\text{head}) \times P(\text{6}) = \frac{1}{2} \times \frac{1}{6} = \frac{1}{12} \]

To express this probability as a decimal, we can perform the division:

\[ \frac{1}{12} \approx 0.0833 \]

Rounding this value to the nearest hundredth, we get:

\[ 0.08 \]

Thus, the probability of obtaining a head and rolling a 6 is 0.08.