If you take a 15.0-mL portion of the stock solution and dilute it to a total volume of 0.700L , what will be the concentration of the final solution?

Answer 1

Let M1 be the concentration of the stock solution.
Recall the formula relating molarity and volume:
M1 * V1 = M2 * V2
where
V1 = initial volume
V2 = final volume
M2 = final concentration
Substituting,
M1 * (15.0 mL) = (700 mL) * M2
We solve for M2:
M2 = M1 * 15/700
M2 = 0.0214 * M1

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