since F ∝ 1/r^2, 1/(2r)^2 = 1/4 * 1/r^2, so the pull would be 1/4 as much.
Of course, that ignores the tremendous torque on the ladder caused by the earth's spin! :-)
If you stood atop a ladder that was so tall that you were twice as far from Earth's center, how would your weight compare with its present value?
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