The probability of landing on a vowel on the first spin is 2/6, because there are two vowels (E and I) out of the six sectors.
After the first spin, there are five sectors remaining, but only one leads to landing on a Q. Therefore, the probability of landing on Q on the second spin, given that a vowel was landed on the first spin, is 1/5.
To find the probability of both events happening, we multiply the probabilities:
P(vowel, then Q) = (2/6) x (1/5)
Simplifying this expression gives us:
P(vowel, then Q) = 1/15
Therefore, the answer is not listed, but the correct answer is:
Not listed. The probability is 1/15.
If you spin the spinner below twice, what is P(vowel, then Q)?
A spinner is divided evenly into 6 sectors. From the top of the spinner clockwise, the sectors are labeled F, G, E, I, Q, and O. The spinner arrow points to the sector labeled Q.
A. one-tenth
B. one-ninth
C. start fraction 2 over 9 end fraction
D. start fraction 1 over 12 end fraction
9 / 18
2 answers
That's strange, I see 3 vowels,
E, I, and O
E, I, and O