If you reacted 100.0 g of carbon tetrachloride (CCl4) with excess antimony fluoride (SbF3), how many grams of carbon dichloride difluoride would be produced?

Answer 1

Do you have an equation for the reaction?
I assume the reaction is
3CCl4 + 2SbF3 ==> 3CCl2F2 + 2SbCl3

mols CCl4 = grams/molar mass = ?
Using the coefficients in the balanced equation, convert mols CCl4 to mols CCl2F2.
Then g CCl2F2 = mols CCl2F2 x molar mass CCl2F2 = ?