If you randomly choose two different numbers from 1 to 10, what is the probability that one number is one more than the other?

Answer 1

If they are different numbers, the probability that one is greater than the other one is equal to 1.
Goodness.

Answer 2

you could have picked 1-2, 2-3, 3-4, 4-5, 5-6 , 6-7, 7-8, 8-9, 9-10 or their reverses.

so prob(your event) = 18/100 = 9/50

Answer 3

1/5

tangina basta yan ung tama

Answer 4

There are 10!/8!2!=45 possible combinations that you will get given that you draw two numbers at a time. Then, there are possible combinations you could draw where numbers are consecutive e.g. (1,2),(2,3),(3,4),(4,5),(5,6),(6,7),(7,8),(8,9),(9,10) and vice-versa for a total of 9 possible combinations. Thus, the probability that one number is one more than the other is 9/45 or 1/5. Hope it helps. :)