If you place 10.0 L of propanol (C3H8O) in a sealed room that is 3 m long, 2.75 m wide, and 2.5 m high, will all the propanol evaporate? If some liquid remains, how much will there be? The vapor pressure of propanol is 10.7 torr at 25 °C, and the density of the liquid at this temperature is 0.804 g/mL.

Question

DrBob222 · Answer

I would convert the measurements to cm; therefore, 300 cm x 275 cm x 250 cm = 2.06E7 cc.
Convert cc to L = 2.05E7 cc x (1L/1000cc) = approx 2.06E4 L but you need to confirm all of these numbers and if needed with more accuracy.
Then PV = nRT.
Substitute 10.7 torr(converted to atm) \ 10.7/760 = ?
Use V from above in the room.
You know R and T (in kelvin), solve for n = mols and convert to grams. Compare with 10.0L propanol converted to grams with density. Post your work if you get stuck.