Part A
Distance = 29•(2•23) = 1334 m
Displacement =0 (he started and finished at the same point)
Average velocity= displacement/time = 0
Average speed = distance/time = 1334/2.5•3600=0.148 m/s
Part B
Distance 29.5•(2•23)= 1357 m.
Displacement =23 m
Average velocity= displacement/time =23/2.5•3600 =0.00256 m/s
Average speed = distance/time = 1357/2.5•3600=0.1508 m/s
If you have swam one lap in a swimming pool, that means you have swam from one end to the other and back. In 2.5 h, a swimmer makes exactly 29 laps in a swimming pool that is 23 m long. Determine the distance the swimmer traveled, the total displacement of the swimmer, the swimmer's average velocity, and the swimmer's average speed.
If instead, the swimmer makes 29.5 laps in the same pool in 2.5 h, determine the total distance the swimmer traveled, the swimmer's total displacement, the swimmer's average velocity, and the swimmer's average speed.
1 answer
1 answer